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Popular >

extreme f(x)=f(x)=xsqrt(x^2+4)

Solution

extreme points

f (x) = f (x) = x x^{2} + 4

Solution

None

Solution steps

f^{'} (x) = \frac{2 x ^{2} + 4}{x ^{2} + 4}

Find intervals:

None

None

Popular Examples

extreme f(x)=2x^3+3x^2-120x+9 extreme points

f (x) = 2 x^{3} + 3 x^{2} - 120 x + 9

extreme f(x)=x^3+12x^2-27x+6,-10<= x<= 0 extreme points

f (x) = x^{3} + 12 x^{2} - 27 x + 6, - 10 \leq x \leq 0

extreme y=(2x^2-1)^2 extreme points

y = (2 x^{2} - 1)^{2}

extreme f(x)= 6/(-4x+2)extreme points

f (x) = \frac{6}{- 4 x + 2}

extreme f(y)=x^{y+1}extreme points

f (y) = x^{y + 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=f(x)=xsqrt(x^2+4) ?
The extreme f(x)=f(x)=xsqrt(x^2+4) is None