What is the extreme f(x)=8ex-y-5xy+6y^2 ?

The extreme f(x)=8ex-y-5xy+6y^2 is Saddle((96e-5}{25},\frac{8e)/5)

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extreme f(x)=8ex-y-5xy+6y^2

extreme points

f (x) = 8 e x - y - 5 x y + 6 y^{2}

Saddle (\frac{96 e - 5}{25}, \frac{8 e}{5})

Solution steps

Find the critical points:

(\frac{96 e - 5}{25}, \frac{8 e}{5})

\frac{\partial ^{2} f}{\partial x ^{2}} = 12

D (x, y) = - 25

Check the sign of at each critical point

Check critical point

(\frac{96 e - 5}{25}, \frac{8 e}{5}) :

Saddle

Saddle (\frac{96 e - 5}{25}, \frac{8 e}{5})

f (x) = - \frac{1}{50} x^{2} + 1.85 x - 8.5

f (x) = 2 x^{3} - 3 x^{2} - 6 x

f (x, y) = x^{2} - 2 \cdot x + 2 \cdot y^{2} - 4 \cdot y

f (x) = 0.00397 t^{2} - 0.593 t + 33.718

f (x) = f (x) = e x - x, - 4 \leq x \leq 2

What is the extreme f(x)=8ex-y-5xy+6y^2 ?
The extreme f(x)=8ex-y-5xy+6y^2 is Saddle((96e-5}{25},\frac{8e)/5)