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Popular >

extreme f(x)=2x^2+16x-5

Solution

extreme points

f (x) = 2 x^{2} + 16 x - 5

Solution

Minimum (- 4, - 37)

Solution steps

f^{'} (x) = 4 x + 16

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

2 x^{2} + 16 x - 5 : - 37

Minimum (- 4, - 37)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+16x-5 ?
The extreme f(x)=2x^2+16x-5 is Minimum(-4,-37)