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midpoint
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symmetry (x+1)^2-4symmetry inverse of f(x)=pi-arccos(2x+1)inverse distance (1,-1),(2,-6)distance vertices y=x^2-2x-24vertices range of f(x)=sqrt(x^2-6x+8)range
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-4),(4,-4) ?
The midpoint (-2,-4),(4,-4) is (1,-4)