What is the domain of f(x)=sqrt(((x^2-2x))/(x-1)) ?

The domain of f(x)=sqrt(((x^2-2x))/(x-1)) is 0 = 2

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domain of f(x)=sqrt(((x^2-2x))/(x-1))

domain

f (x) = \frac{( x ^{2} - 2 x )}{x - 1}

0 \leq x < 1 or x \geq 2

Interval Notation

[0, 1) \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

0 \leq x < 1 or x \geq 2

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

0 \leq x < 1 or x \geq 2

5 x - 2 y = 14

f (x) = arctan (\frac{x - 1}{x + 1})

f (x) = x^{3} - 4 x

f (x) = \frac{- 7 x + 9}{- 4 x - 3}

f (x) = \frac{x ^{2} - 9}{x - 5}

What is the domain of f(x)=sqrt(((x^2-2x))/(x-1)) ?
The domain of f(x)=sqrt(((x^2-2x))/(x-1)) is 0<= x<1\lor x>= 2