What is the domain of f(x)=sqrt((x^2-4)/(x-2)) ?

The domain of f(x)=sqrt((x^2-4)/(x-2)) is -2 2

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domain of f(x)=sqrt((x^2-4)/(x-2))

domain

f (x) = \frac{x ^{2} - 4}{x - 2}

- 2 \leq x < 2 or x > 2

Interval Notation

[- 2, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

- 2 \leq x < 2 or x > 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 2 \leq x < 2 or x > 2

(- 3, - 1), (- 2, 3)

f (y) = \frac{d y}{y}

f (x) = 3 + ln (x)

f (x) = t^{2} - 5

\frac{ln ( x - 1 )}{x - 1}

What is the domain of f(x)=sqrt((x^2-4)/(x-2)) ?
The domain of f(x)=sqrt((x^2-4)/(x-2)) is -2<= x<2\lor x>2