What is the critical f(x)=(e^{2x})/(x-3) ?

The critical f(x)=(e^{2x})/(x-3) is x= 7/2

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critical f(x)=(e^{2x})/(x-3)

critical points

f (x) = \frac{e ^{2 x}}{x - 3}

x = \frac{7}{2}

Solution steps

\frac{e ^{2 x}}{x - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{7}{2}, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{e ^{2 x}}{x - 3} : x < 3 or x > 3

\frac{e ^{2 x}}{x - 3}

is not defined at

x = 3

, therefore:

x = \frac{7}{2}

f (x) = x^{2} + 7

f (x) = \frac{x + 3}{2 x - 1}

f (x) = x^{2} + 7 x + 5

\frac{2 x ^{2} - 5 x - 12}{x ^{2} - 16}

f (x) = 2 x + 3 y = - 24

What is the critical f(x)=(e^{2x})/(x-3) ?
The critical f(x)=(e^{2x})/(x-3) is x= 7/2