What is the inverse of f(x)=6((x-3)/7)^{1/5} ?

The inverse of f(x)=6((x-3)/7)^{1/5} is (7x^5)/(7776)+3

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inverse of f(x)=6((x-3)/7)^{1/5}

inverse

f (x) = 6 (\frac{x - 3}{7})^{\frac{1}{5}}

\frac{7 x ^{5}}{7776} + 3

Solution steps

y = 6 (\frac{x - 3}{7})^{\frac{1}{5}}

Replace

x

with

y

x = 6 (\frac{y - 3}{7})^{\frac{1}{5}}

Solve for

y, x = 6 (\frac{y - 3}{7})^{\frac{1}{5}}

\frac{7 x ^{5}}{7776} + 3

f (x) = \frac{x + 1}{8}

f (x) = (x + 6)^{2} - 3

f (x) = - x - 2

f (x) = ln (x - 1)

f (x) = x^{2} + 5

What is the inverse of f(x)=6((x-3)/7)^{1/5} ?
The inverse of f(x)=6((x-3)/7)^{1/5} is (7x^5)/(7776)+3