What is the inverse of f(x)=(x+6)^2-3 ?

The inverse of f(x)=(x+6)^2-3 is sqrt(x+3)-6,-sqrt(x+3)-6

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inverse of f(x)=(x+6)^2-3

inverse

f (x) = (x + 6)^{2} - 3

x + 3 - 6, - x + 3 - 6

Solution steps

y = (x + 6)^{2} - 3

Replace

x

with

y

x = (y + 6)^{2} - 3

Solve for

y, x = (y + 6)^{2} - 3

x + 3 - 6, - x + 3 - 6

f (x) = - x - 2

f (x) = ln (x - 1)

f (x) = x^{2} + 5

\frac{e ^{x} + 1}{e ^{x} - 2}

f (x) = \frac{2 x ^{2}}{x ^{2} - 9}

What is the inverse of f(x)=(x+6)^2-3 ?
The inverse of f(x)=(x+6)^2-3 is sqrt(x+3)-6,-sqrt(x+3)-6