What is the asymptotes of f(x)=(x^2+3x-4)/(x-1) ?

The asymptotes of f(x)=(x^2+3x-4)/(x-1) is Slant: y=x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+3x-4)/(x-1)

asymptotes

f (x) = \frac{x ^{2} + 3 x - 4}{x - 1}

Slant : y = x + 4

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 3 x - 4}{x - 1} :

None

Horizontal Asymptotes of

\frac{x ^{2} + 3 x - 4}{x - 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 3 x - 4}{x - 1} : y = x + 4

Slant : y = x + 4

f (x) = \frac{1}{x ^{2} - 16}

f (x) = lo g_{3} (x - 2)

f (x) = \frac{12 x}{x ^{2} + 4}

f (x) = x^{3} \cdot e^{(- x)}

f (x) = cot (\frac{x}{2} - \frac{π}{4}) + 1

What is the asymptotes of f(x)=(x^2+3x-4)/(x-1) ?
The asymptotes of f(x)=(x^2+3x-4)/(x-1) is Slant: y=x+4