en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=x^2-6x+10

Solution

range

f (x) = x^{2} - 6 x + 10

Solution

f (x) \geq 1

+1

Interval Notation

[1, \infty)

Solution steps

Vertex of

x^{2} - 6 x + 10 :

Minimum

(3, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (3, 1)

f (x) \geq 1

Popular Examples

range of f(x)= x/(sqrt(4-x^2))range

f (x) = \frac{x}{4 - x ^{2}}

range of f(x)=(-x^2+6x-8)^{(1/2)}range

f (x) = (- x^{2} + 6 x - 8)^{(\frac{1}{2})}

domain of f(x)=sqrt(x-3)+4 domain

f (x) = x - 3 + 4

domain of f(x)= 1/(x+2)+9 domain

f (x) = \frac{1}{x + 2} + 9

inverse of f(x)=(x-1)/(2+x)inverse

f (x) = \frac{x - 1}{2 + x}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-6x+10 ?
The range of f(x)=x^2-6x+10 is f(x)>= 1