What is the inverse of f(x)=6x^2+1 ?

The inverse of f(x)=6x^2+1 is sqrt((x-1)/6),-sqrt((x-1)/6)

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inverse of f(x)=6x^2+1

inverse

f (x) = 6 x^{2} + 1

\frac{x - 1}{6}, - \frac{x - 1}{6}

Solution steps

y = 6 x^{2} + 1

Replace

x

with

y

x = 6 y^{2} + 1

Solve for

y, x = 6 y^{2} + 1

\frac{x - 1}{6}, - \frac{x - 1}{6}

(1.6, 0.3365), (2.4, 0.574)

f (x) = x^{3} - 12 x + 3

\frac{3}{2} sin (2 π x)

f (x) = t^{2} - 10 t + 25

f (x) = \frac{1}{x ^{2} + 1}

What is the inverse of f(x)=6x^2+1 ?
The inverse of f(x)=6x^2+1 is sqrt((x-1)/6),-sqrt((x-1)/6)