What is the inverse of f(x)=(sqrt(3x-2))/5 ?

The inverse of f(x)=(sqrt(3x-2))/5 is (25x^2+2)/3

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inverse of f(x)=(sqrt(3x-2))/5

inverse

f (x) = \frac{3 x - 2}{5}

\frac{25 x ^{2} + 2}{3}

Solution steps

y = \frac{3 x - 2}{5}

Replace

x

with

y

x = \frac{3 y - 2}{5}

Solve for

y, x = \frac{3 y - 2}{5}

\frac{25 x ^{2} + 2}{3}

25 - x^{2} + x + 2

f (x) = 2 x^{3} - 30 x^{2} + 144 x + 8

f (x) = \frac{6 x ^{2}}{x - 6}

f (x) = \frac{x}{x + 1}

What is the inverse of f(x)=(sqrt(3x-2))/5 ?
The inverse of f(x)=(sqrt(3x-2))/5 is (25x^2+2)/3