What is the extreme f(x)=2x^3-30x^2+144x+8 ?

The extreme f(x)=2x^3-30x^2+144x+8 is Maximum(4,232),Minimum(6,224)

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extreme f(x)=2x^3-30x^2+144x+8

extreme points

f (x) = 2 x^{3} - 30 x^{2} + 144 x + 8

Maximum (4, 232), Minimum (6, 224)

Solution steps

f^{'} (x) = 6 x^{2} - 60 x + 144

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 4

into

2 x^{3} - 30 x^{2} + 144 x + 8 : 232

Maximum (4, 232)

Plug

x = 6

into

2 x^{3} - 30 x^{2} + 144 x + 8 : 224

Minimum (6, 224)

Maximum (4, 232), Minimum (6, 224)

f (x) = \frac{6 x ^{2}}{x - 6}

f (x) = \frac{x}{x + 1}

f (x) = \frac{x ^{2} - 1}{x ^{2} + 2 x - 3}

x = - 19, (6, 1)

What is the extreme f(x)=2x^3-30x^2+144x+8 ?
The extreme f(x)=2x^3-30x^2+144x+8 is Maximum(4,232),Minimum(6,224)