What is the domain of f(x)=sqrt(x^2-6) ?

The domain of f(x)=sqrt(x^2-6) is x = sqrt(6)

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domain of f(x)=sqrt(x^2-6)

domain

f (x) = x^{2} - 6

x \leq - 6 or x \geq 6

Interval Notation

(- \infty, - 6] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 6

The function domain

x \leq - 6 or x \geq 6

2 (x + 3)^{2} - 4

\frac{2 x - 1}{x ^{2} + 1}

f (x) = (x - 2) (x - 3) (x - 4)

(- 23, 3), (- 25, - 10)

f (x) = \frac{x + 5}{x ^{2} - 49}

What is the domain of f(x)=sqrt(x^2-6) ?
The domain of f(x)=sqrt(x^2-6) is x<=-sqrt(6)\lor x>= sqrt(6)