What is the inverse of f(x)=2x^2+3x+5 ?

The inverse of f(x)=2x^2+3x+5 is (-3+sqrt(8x-31))/4 ,(-3-sqrt(8x-31))/4

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inverse of f(x)=2x^2+3x+5

inverse

f (x) = 2 x^{2} + 3 x + 5

\frac{- 3 + 8 x - 31}{4}, \frac{- 3 - 8 x - 31}{4}

Solution steps

y = 2 x^{2} + 3 x + 5

Replace

x

with

y

x = 2 y^{2} + 3 y + 5

Solve for

y, x = 2 y^{2} + 3 y + 5

\frac{- 3 + 8 x - 31}{4}, \frac{- 3 - 8 x - 31}{4}

4 csc (\frac{5 π}{3} x - \frac{20 π}{3})

f (x) = x^{2} + 3 \cdot x + 2

f (x) = x^{2} - 10

f (x) = \frac{8}{3 x + 1}

20 x - 4

What is the inverse of f(x)=2x^2+3x+5 ?
The inverse of f(x)=2x^2+3x+5 is (-3+sqrt(8x-31))/4 ,(-3-sqrt(8x-31))/4