What is the perpendicular y=-2x+6,(1,6) ?

The perpendicular y=-2x+6,(1,6) is y= 1/2 x+11/2

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perpendicular y=-2x+6,(1,6)

perpendicular

y = - 2 x + 6, (1, 6)

y = \frac{1}{2} x + \frac{11}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 2 x + 6

that passes through

(1, 6)

Find the slope of

y = - 2 x + 6 : m = - 2

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(1, 6) : y = \frac{1}{2} x + \frac{11}{2}

y = \frac{1}{2} x + \frac{11}{2}

(- 2, - 4), (- 7, - 5)

f (x) = x^{3} - 3 x + 8

5 x + 6 y = 7, (5, - 2)

f (x) = \frac{7 x}{x + 2}

x^{3} + 3 (27 - 3 x^{2})^{2} + 7

What is the perpendicular y=-2x+6,(1,6) ?
The perpendicular y=-2x+6,(1,6) is y= 1/2 x+11/2