What is the domain of f(x)=sqrt(\sqrt{x^2-49)-49} ?

The domain of f(x)=sqrt(\sqrt{x^2-49)-49} is x = 35sqrt(2)

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domain of f(x)=sqrt(\sqrt{x^2-49)-49}

domain

f (x) = x^{2} - 49 - 49

x \leq - 352 or x \geq 352

Interval Notation

(- \infty, - 352] \cup [352, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 352 or x \geq 352

The function domain

x \leq - 352 or x \geq 352

\frac{( x ^{3} - x )}{1 + x ^{2}}

f (x) = \frac{6 x - 12 x ^{9}}{3 x ^{3} + 7}

f (x) = \frac{( 2 x - 1 )}{x + 3}

h (x) = x - 10

f (x) = \frac{2}{4 x - 3}

What is the domain of f(x)=sqrt(\sqrt{x^2-49)-49} ?
The domain of f(x)=sqrt(\sqrt{x^2-49)-49} is x<=-35sqrt(2)\lor x>= 35sqrt(2)