What is the range of f(x)=(2/3)^x ?

The range of f(x)=(2/3)^x is f(x)>0

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range of f(x)=(2/3)^x

range

f (x) = (\frac{2}{3})^{x}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = 0

f (x) > 0

f (x) = \frac{4 + x}{3 - x}

r^{2} + 8.12 r + 3364

y = - x^{2} + 2 x - 4

(2) (8.8)

f (x) = \frac{2 x ^{2} - x - 3}{x ^{2} + 1}