What is the inverse of f(x)=9x^2-2 ?

The inverse of f(x)=9x^2-2 is (sqrt(x+2))/3 ,-(sqrt(x+2))/3

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inverse of f(x)=9x^2-2

inverse

f (x) = 9 x^{2} - 2

\frac{x + 2}{3}, - \frac{x + 2}{3}

Solution steps

y = 9 x^{2} - 2

Replace

x

with

y

x = 9 y^{2} - 2

Solve for

y, x = 9 y^{2} - 2

\frac{x + 2}{3}, - \frac{x + 2}{3}

3 x + 5 y = 15, (3, 2)

- 1.5

f (x) = (5 x + 1)^{3}

f (x) = \frac{1}{10} x^{5} - 5 x^{3}

y = \frac{49}{x ^{2}}

What is the inverse of f(x)=9x^2-2 ?
The inverse of f(x)=9x^2-2 is (sqrt(x+2))/3 ,-(sqrt(x+2))/3