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Popular >

midpoint (12,5),(10,-7)

Solution

midpoint

(12, 5), (10, - 7)

Solution

(11, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (12, 5), (x_{2}, y_{2}) = (10, - 7)

= (\frac{10 + 12}{2}, \frac{- 7 + 5}{2})

Refine

= (11, - 1)

Popular Examples

extreme f(x)=(x^2)/((x-2)^3)extreme points

f (x) = \frac{x ^{2}}{( x - 2 ) ^{3}}

inverse of f(x)=x^2+2x-3 inverse

f (x) = x^{2} + 2 x - 3

domain of f(x)=[sqrt([5x-15])]+40 domain

f (x) = [[5 x - 15]] + 40

inverse of f(x)= 3/10 x+3/2 inverse

f (x) = \frac{3}{10} x + \frac{3}{2}

asymptotes of f(x)=(4x)/(x^3-4x)asymptotes

f (x) = \frac{4 x}{x ^{3} - 4 x}

Frequently Asked Questions (FAQ)

What is the midpoint (12,5),(10,-7) ?
The midpoint (12,5),(10,-7) is (11,-1)