What is the critical f(x)=-x^2+2x ?

The critical f(x)=-x^2+2x is x=1

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critical f(x)=-x^2+2x

critical points

f (x) = - x^{2} + 2 x

x = 1

Solution steps

- x^{2} + 2 x

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

- x^{2} + 2 x : - \infty < x < \infty

All critical points are in domain

x = 1

3 x^{2} + 2

f (x) = 2 + 5 + 6 x

y = - 1, (8, - 4)

f (x) = \frac{1}{16} (x - 1)^{2} - 4

f (x) = \frac{1 - e ^{x}}{1 + e ^{x}}