What is the perpendicular y=4x+8,(4,-1) ?

The perpendicular y=4x+8,(4,-1) is y=-1/4 x

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perpendicular y=4x+8,(4,-1)

perpendicular

y = 4 x + 8, (4, - 1)

y = - \frac{1}{4} x

Solution steps

Find the line

y = mx + b

perpendicular to

y = 4 x + 8

that passes through

(4, - 1)

Find the slope of

y = 4 x + 8 : m = 4

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(4, - 1) : y = - \frac{1}{4} x

y = - \frac{1}{4} x

f (x) = \frac{1}{2} cos (\frac{2 π}{3} x - \frac{1}{5})

f (x) = - 4 x - 8

\frac{\frac{x}{x + 8}}{\frac{x}{x + 8} + 8}

x^{2} sin (\frac{1}{x})

f (x) = \frac{( 6 + x ^{4} )}{x ^{2} - x ^{4}}

What is the perpendicular y=4x+8,(4,-1) ?
The perpendicular y=4x+8,(4,-1) is y=-1/4 x