What is the shift f(x)= 1/2 cos((2pi)/3 x-1/5) ?

The shift f(x)= 1/2 cos((2pi)/3 x-1/5) is Phase: 3/(10pi), Vertical:0

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shift f(x)= 1/2 cos((2pi)/3 x-1/5)

shift

f (x) = \frac{1}{2} cos (\frac{2 π}{3} x - \frac{1}{5})

Phase : \frac{3}{10 π}, Vertical : 0

Solution steps

f (x) = \frac{1}{2} cos (\frac{2 π}{3} x - \frac{1}{5})

g (B x - C) = cos (\frac{2 π}{3} x - \frac{1}{5}), B = \frac{2 π}{3}, C = \frac{1}{5}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{1}{5}}{\frac{2 π}{3}}

\frac{3}{10 π}

The vertical shift

D

0

0

f (x) = - 4 x - 8

\frac{\frac{x}{x + 8}}{\frac{x}{x + 8} + 8}

x^{2} sin (\frac{1}{x})

f (x) = \frac{( 6 + x ^{4} )}{x ^{2} - x ^{4}}

f (x) = x^{2} - 4

What is the shift f(x)= 1/2 cos((2pi)/3 x-1/5) ?
The shift f(x)= 1/2 cos((2pi)/3 x-1/5) is Phase: 3/(10pi), Vertical:0