What is the inverse of f(x)=(7x-8)/(9x+1) ?

The inverse of f(x)=(7x-8)/(9x+1) is (-8-x)/(9x-7)

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inverse of f(x)=(7x-8)/(9x+1)

inverse

f (x) = \frac{7 x - 8}{9 x + 1}

\frac{- 8 - x}{9 x - 7}

Solution steps

y = \frac{7 x - 8}{9 x + 1}

Replace

x

with

y

x = \frac{7 y - 8}{9 y + 1}

Solve for

y, x = \frac{7 y - 8}{9 y + 1}

\frac{- 8 - x}{9 x - 7}

4 x + 7 y = 8, (4, - 2)

f (x) = \frac{8 - x}{x + 8}

\frac{- 6 x + 12}{5 x - 10}

f (x) = \frac{x + 10}{x ^{2} - 100}

x = 9 (y - 7)^{2} + 5

What is the inverse of f(x)=(7x-8)/(9x+1) ?
The inverse of f(x)=(7x-8)/(9x+1) is (-8-x)/(9x-7)