What is the perpendicular 4x+7y=8,(4,-2) ?

The perpendicular 4x+7y=8,(4,-2) is y= 7/4 x-9

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perpendicular 4x+7y=8,(4,-2)

perpendicular

4 x + 7 y = 8, (4, - 2)

y = \frac{7}{4} x - 9

Solution steps

Find the line

y = mx + b

perpendicular to

4 x + 7 y = 8

that passes through

(4, - 2)

Find the slope of

4 x + 7 y = 8 : m = - \frac{4}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{4}

Find the line with slope m=

\frac{7}{4}

and passing through

(4, - 2) : y = \frac{7}{4} x - 9

y = \frac{7}{4} x - 9

f (x) = \frac{8 - x}{x + 8}

\frac{- 6 x + 12}{5 x - 10}

f (x) = \frac{x + 10}{x ^{2} - 100}

x = 9 (y - 7)^{2} + 5

f (x) = \frac{x + 2}{x - 6}

What is the perpendicular 4x+7y=8,(4,-2) ?
The perpendicular 4x+7y=8,(4,-2) is y= 7/4 x-9