What is the domain of f(t)=sqrt(t+6) ?

The domain of f(t)=sqrt(t+6) is t>=-6

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domain of f(t)=sqrt(t+6)

domain

f (t) = t + 6

t \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 6

The function domain

t \geq - 6

f (x) = \frac{x ^{2} + 14}{x ^{2} - 4 x - 5}

\frac{x ^{2} + x - 6}{x ^{2} + 6 x + 9}

f (x) = 4 (x + 3)^{2} - 16

2 x - 3

x^{2} + 12