What is the domain of f(x)=(x^2+14)/(x^2-4x-5) ?

The domain of f(x)=(x^2+14)/(x^2-4x-5) is x 5

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domain of f(x)=(x^2+14)/(x^2-4x-5)

domain

f (x) = \frac{x ^{2} + 14}{x ^{2} - 4 x - 5}

x < - 1 or - 1 < x < 5 or x > 5

Interval Notation

(- \infty, - 1) \cup (- 1, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 1

The function domain

x < - 1 or - 1 < x < 5 or x > 5

\frac{x ^{2} + x - 6}{x ^{2} + 6 x + 9}

f (x) = 4 (x + 3)^{2} - 16

2 x - 3

x^{2} + 12

f (x) = x^{2} + 4 x + 5

What is the domain of f(x)=(x^2+14)/(x^2-4x-5) ?
The domain of f(x)=(x^2+14)/(x^2-4x-5) is x<-1\lor-1<x<5\lor x>5