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Popular >

range of f(x)=x^2+12

Solution

range

f (x) = x^{2} + 12

Solution

f (x) \geq 12

+1

Interval Notation

[12, \infty)

Solution steps

Vertex of

x^{2} + 12 :

Minimum

(0, 12)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (0, 12)

f (x) \geq 12

Popular Examples

m = - 2

domain of f(x)=ln(x+sqrt(x^2+1))domain

f (x) = ln (x + x^{2} + 1)

intercepts of f(x)=(4x-20)/(x-5)intercepts

f (x) = \frac{4 x - 20}{x - 5}

slope ofintercept 3x-2y=12 slope intercept

3 x - 2 y = 12

range of 2x^2-5 range

2 x^{2} - 5

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+12 ?
The range of f(x)=x^2+12 is f(x)>= 12