en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=x^2-6x+9

Solution

range

f (x) = x^{2} - 6 x + 9

Solution

f (x) \geq 0

+1

Interval Notation

[0, \infty)

Solution steps

Vertex of

x^{2} - 6 x + 9 :

Minimum

(3, 0)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (3, 0)

f (x) \geq 0

Popular Examples

domain of f(x)=((2x+4))/(x^2-x-12)domain

f (x) = \frac{( 2 x + 4 )}{x ^{2} - x - 12}

domain of f(x)=sqrt(4-x^2)domain

f (x) = 4 - x^{2}

extreme x^3-3x+1 extreme points

x^{3} - 3 x + 1

domain of f(x)=(x(x+1))/(x-1)domain

f (x) = \frac{x ( x + 1 )}{x - 1}

domain of f(x)=3x-x^2 domain

f (x) = 3 x - x^{2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-6x+9 ?
The range of f(x)=x^2-6x+9 is f(x)>= 0