What is the domain of f(x)=sqrt(4-x^2) ?

The domain of f(x)=sqrt(4-x^2) is -2<= x<= 2

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domain of f(x)=sqrt(4-x^2)

domain

f (x) = 4 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

x^{3} - 3 x + 1

f (x) = \frac{x ( x + 1 )}{x - 1}

f (x) = 3 x - x^{2}

y = x^{3} + 2

f (x) = x (x - 2)

What is the domain of f(x)=sqrt(4-x^2) ?
The domain of f(x)=sqrt(4-x^2) is -2<= x<= 2