What is the domain of f(x)=sqrt(x-2) ?

The domain of f(x)=sqrt(x-2) is x>= 2

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domain of f(x)=sqrt(x-2)

domain

f (x) = x - 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

2 x^{3} - 10 x^{2} - 8 x + 40

f (x) = \frac{x + 9}{x - 5}

6 x + 6

\frac{x ^{2} - 2 x - 15}{x ^{2} + 4 x}

f (x) = (x + 2)^{2}, x \geq - 2