What is the domain of (sqrt(x-3))^2 ?

The domain of (sqrt(x-3))^2 is x>= 3

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domain of (sqrt(x-3))^2

domain

(x - 3)^{2}

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = \frac{( 2 x - 3 )}{x + 1}

sin (2) (x - \frac{π}{2}) + 1

\frac{7 e ^{x}}{7 + e ^{x}}

25 h^{2} + 28 h - 56

r (x) = \frac{x ( x - 18 ) ^{2}}{( x - 18 )}