What is the domain of (sqrt(2x-3))/(x^2-5x+4) ?

The domain of (sqrt(2x-3))/(x^2-5x+4) is 3/2 4

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domain of (sqrt(2x-3))/(x^2-5x+4)

domain

\frac{2 x - 3}{x ^{2} - 5 x + 4}

\frac{3}{2} \leq x < 4 or x > 4

Interval Notation

[\frac{3}{2}, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{2}

Find undefined (singularity) points:

x = 4, x = 1

Combine real regions and undefined points for final function domain

\frac{3}{2} \leq x < 4 or x > 4

f (x) = x^{\frac{3}{4}} - 9 x^{\frac{1}{4}}

- x + 3 - 2

f (x) = x^{5} - 2

f (x) = \frac{( x + 3 )}{x ^{2} - 4 x + 3}

f (x) = x - 14

What is the domain of (sqrt(2x-3))/(x^2-5x+4) ?
The domain of (sqrt(2x-3))/(x^2-5x+4) is 3/2 <= x<4\lor x>4