What is the domain of (65)/((1-8x)^2) ?

The domain of (65)/((1-8x)^2) is x 1/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (65)/((1-8x)^2)

domain

\frac{65}{( 1 - 8 x ) ^{2}}

x < \frac{1}{8} or x > \frac{1}{8}

Interval Notation

(- \infty, \frac{1}{8}) \cup (\frac{1}{8}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{8}

The function domain

x < \frac{1}{8} or x > \frac{1}{8}

x e^{\frac{1}{x}}

\frac{4 x ^{2} + 4 x + 1}{2 x ^{3} + 8 x ^{2}}

(8, 1), (- 2, - 5)

f (x) = \frac{( 4 x ^{2} - 1 )}{∣ 2 x + 1 ∣}

x^{2} + 16

What is the domain of (65)/((1-8x)^2) ?
The domain of (65)/((1-8x)^2) is x< 1/8 \lor x> 1/8