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Popular >

midpoint (-8,-2),(-7,8)

Solution

midpoint

(- 8, - 2), (- 7, 8)

Solution

(- \frac{15}{2}, 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 8, - 2), (x_{2}, y_{2}) = (- 7, 8)

= (\frac{- 7 - 8}{2}, \frac{8 - 2}{2})

Refine

= (- \frac{15}{2}, 3)

Popular Examples

domain of f(x)= 1/(sqrt(6+x))domain

f (x) = \frac{1}{6 + x}

range of f(x)= 2/(sqrt(x-3))range

f (x) = \frac{2}{x - 3}

asymptotes of f(x)=(x-6)/(x^2+2)asymptotes

f (x) = \frac{x - 6}{x ^{2} + 2}

inverse of f(x)=sqrt(x^2-8x)inverse

f (x) = x^{2} - 8 x

inverse of f(x)= 5/(2-x),x<2 inverse

f (x) = \frac{5}{2 - x}, x < 2

Frequently Asked Questions (FAQ)

What is the midpoint (-8,-2),(-7,8) ?
The midpoint (-8,-2),(-7,8) is (-15/2 ,3)