What is the inverse of f(x)= 1/(x^3)+3 ?

The inverse of f(x)= 1/(x^3)+3 is cube root of 1/(x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/(x^3)+3

inverse

f (x) = \frac{1}{x ^{3}} + 3

Solution steps

y = \frac{1}{x ^{3}} + 3

Replace

x

with

y

x = \frac{1}{y ^{3}} + 3

Solve for

y, x = \frac{1}{y ^{3}} + 3

7 cos (8 (x + \frac{π}{6}))

lo g_{\frac{1}{3}} (\frac{5 + x}{x})

f (x) = 3 x

f (x) = \frac{- 4}{x ^{2} - 1}

y = 3 x + 1, (- 3, 6)

What is the inverse of f(x)= 1/(x^3)+3 ?
The inverse of f(x)= 1/(x^3)+3 is cube root of 1/(x-3)