What is the domain of (3x^2-13x+4)/(2x^2+7x-15) ?

The domain of (3x^2-13x+4)/(2x^2+7x-15) is x 3/2

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domain of (3x^2-13x+4)/(2x^2+7x-15)

domain

\frac{3 x ^{2} - 13 x + 4}{2 x ^{2} + 7 x - 15}

x < - 5 or - 5 < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - 5) \cup (- 5, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - 5

The function domain

x < - 5 or - 5 < x < \frac{3}{2} or x > \frac{3}{2}

\frac{8}{( x - 1 ) ( x + 2 )}

\frac{x}{x ^{2} + 4}

y = tan (x)

(8, 10), (- 2, 14)

f (x) = x^{2} - 2 x

What is the domain of (3x^2-13x+4)/(2x^2+7x-15) ?
The domain of (3x^2-13x+4)/(2x^2+7x-15) is x<-5\lor-5<x< 3/2 \lor x> 3/2