What is the inverse of f(x)=\sqrt[3]{x}+9 ?

The inverse of f(x)=\sqrt[3]{x}+9 is x^3-27x^2+243x-729

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inverse of f(x)=\sqrt[3]{x}+9

inverse

x^{3} - 27 x^{2} + 243 x - 729

Solution steps

Replace

x

with

y

Solve for

x^{3} - 27 x^{2} + 243 x - 729

f (x) = \frac{x ^{2}}{x + 9}

f (x) = \frac{x + 3}{2 - 3 x}

f (x) = 10 x + 1

f (x) = \frac{x ^{2} + x - 6}{3 x + 3}

What is the inverse of f(x)=\sqrt[3]{x}+9 ?
The inverse of f(x)=\sqrt[3]{x}+9 is x^3-27x^2+243x-729