What is the inverse of y=(2x^2-1)/4 ?

The inverse of y=(2x^2-1)/4 is sqrt((4x+1)/2),-sqrt((4x+1)/2)

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inverse of y=(2x^2-1)/4

inverse

y = \frac{2 x ^{2} - 1}{4}

\frac{4 x + 1}{2}, - \frac{4 x + 1}{2}

Solution steps

y = \frac{2 x ^{2} - 1}{4}

Replace

x

with

y

x = \frac{2 y ^{2} - 1}{4}

Solve for

y, x = \frac{2 y ^{2} - 1}{4}

\frac{4 x + 1}{2}, - \frac{4 x + 1}{2}

y = ln (4 x - 10) - 6

f (x) = (x + 1)

5 x + 6 y = - 24

y = x

f (x) = - x + 2

What is the inverse of y=(2x^2-1)/4 ?
The inverse of y=(2x^2-1)/4 is sqrt((4x+1)/2),-sqrt((4x+1)/2)