What is the critical f(x)=(40t)/(t^2+25) ?

The critical f(x)=(40t)/(t^2+25) is t=-5,t=5

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critical f(x)=(40t)/(t^2+25)

critical points

f (x) = \frac{40 t}{t ^{2} + 25}

t = - 5, t = 5

Solution steps

\frac{40 t}{t ^{2} + 25}

Find where

f^{'} (t)

is equal to zero or undefined

t = - 5, t = 5

Identify critical points not in

f (t)

domain

Domain of

\frac{40 t}{t ^{2} + 25} : - \infty < t < \infty

All critical points are in domain

t = - 5, t = 5

\frac{2 x ^{2} - 4}{x + 3}

\frac{5}{x ^{2} - 9}

f (x) = x + y = 2

f (x) = \frac{( 1 )}{x + 2} + 3

f (x) = x^{3} - 6 x^{2} + 9 x + 1

What is the critical f(x)=(40t)/(t^2+25) ?
The critical f(x)=(40t)/(t^2+25) is t=-5,t=5