What is the inverse of f(x)=x^2-2x-15 ?

The inverse of f(x)=x^2-2x-15 is 1+sqrt(x+16),1-sqrt(x+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2-2x-15

inverse

f (x) = x^{2} - 2 x - 15

1 + x + 16, 1 - x + 16

Solution steps

y = x^{2} - 2 x - 15

Replace

x

with

y

x = y^{2} - 2 y - 15

Solve for

y, x = y^{2} - 2 y - 15

1 + x + 16, 1 - x + 16

\frac{0.23 x}{x ^{2} + 25}

f (x) = sin (\frac{2 π x}{3} - 3 π)

f (x) = \frac{1}{2} x - 4

f (x) = \frac{x ^{3} + 5 x ^{2}}{7 x ^{2} - 3}

What is the inverse of f(x)=x^2-2x-15 ?
The inverse of f(x)=x^2-2x-15 is 1+sqrt(x+16),1-sqrt(x+16)