What is the asymptotes of f(x)=(x^2)/(3x+1) ?

The asymptotes of f(x)=(x^2)/(3x+1) is Vertical: x=-1/3 ,Slant: y= 1/3 x-1/9

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asymptotes of f(x)=(x^2)/(3x+1)

asymptotes

f (x) = \frac{x ^{2}}{3 x + 1}

Vertical : x = - \frac{1}{3}, Slant : y = \frac{1}{3} x - \frac{1}{9}

Solution steps

Vertical asymptotes of

\frac{x ^{2}}{3 x + 1} : x = - \frac{1}{3}

Horizontal Asymptotes of

\frac{x ^{2}}{3 x + 1} :

None

Slant Asymptotes of

\frac{x ^{2}}{3 x + 1} : y = \frac{1}{3} x - \frac{1}{9}

Vertical : x = - \frac{1}{3}, Slant : y = \frac{1}{3} x - \frac{1}{9}

f (x) = 7 x^{2} - 3

f (x) = 2 n - 2

f (x) = 3 x - 6 x^{3}

f (x) = 8 x + 13 x^{\frac{8}{13}}

f (x) = x^{5} - 3 x

What is the asymptotes of f(x)=(x^2)/(3x+1) ?
The asymptotes of f(x)=(x^2)/(3x+1) is Vertical: x=-1/3 ,Slant: y= 1/3 x-1/9