What is the inverse of (sqrt(x)-3)/7+10 ?

The inverse of (sqrt(x)-3)/7+10 is 49x^2-938x+4489

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inverse of (sqrt(x)-3)/7+10

inverse

\frac{x - 3}{7} + 10

49 x^{2} - 938 x + 4489

Solution steps

y = \frac{x - 3}{7} + 10

Replace

x

with

y

x = \frac{y - 3}{7} + 10

Solve for

y, x = \frac{y - 3}{7} + 10

49 x^{2} - 938 x + 4489

(\frac{1}{x})^{2} - 4

f (x) = \frac{9 - x ^{2}}{x + 1}

f (x) = \frac{3 x + 4}{2 x - 3}

f (x) = \frac{x ^{2} - 16}{x + 4}

f (x) = x - 1

What is the inverse of (sqrt(x)-3)/7+10 ?
The inverse of (sqrt(x)-3)/7+10 is 49x^2-938x+4489