What is the asymptotes of f(x)=(x^2-2x)/(2x^2+2x-12) ?

The asymptotes of f(x)=(x^2-2x)/(2x^2+2x-12) is Vertical: x=-3,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2-2x)/(2x^2+2x-12)

asymptotes

f (x) = \frac{x ^{2} - 2 x}{2 x ^{2} + 2 x - 12}

Vertical : x = - 3, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x}{2 x ^{2} + 2 x - 12} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - 2 x}{2 x ^{2} + 2 x - 12} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 2 x}{2 x ^{2} + 2 x - 12} :

None

Vertical : x = - 3, Horizontal : y = \frac{1}{2}

\frac{- 5}{1 - x}

f (x) = \frac{3}{x ^{2}}

2 x^{2} (2 + 1)

x = \frac{3}{5}

f (x) = 2 x - 8

What is the asymptotes of f(x)=(x^2-2x)/(2x^2+2x-12) ?
The asymptotes of f(x)=(x^2-2x)/(2x^2+2x-12) is Vertical: x=-3,Horizontal: y= 1/2