What is the inflection x^4-2x^2+3 ?

The inflection x^4-2x^2+3 is (-1/(sqrt(3)), 22/9),(1/(sqrt(3)), 22/9)

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inflection x^4-2x^2+3

inflection points

x^{4} - 2 x^{2} + 3

(- \frac{1}{3}, \frac{22}{9}), (\frac{1}{3}, \frac{22}{9})

Solution steps

f^{''} (x) = 12 x^{2} - 4

Find intervals:

Concave Upward

: - \infty < x < - \frac{1}{3},

Concave Downward

: - \frac{1}{3} < x < \frac{1}{3},

Concave Upward

: \frac{1}{3} < x < \infty

Plug

x = - \frac{1}{3}

into

x^{4} - 2 x^{2} + 3 : \frac{22}{9}

(- \frac{1}{3}, \frac{22}{9})

Plug

x = \frac{1}{3}

into

x^{4} - 2 x^{2} + 3 : \frac{22}{9}

(\frac{1}{3}, \frac{22}{9})

(- \frac{1}{3}, \frac{22}{9}), (\frac{1}{3}, \frac{22}{9})

y = 3 x - 1, (- 1, - 1)

f (x) = \frac{x ^{3}}{2 - x}

f (x) = 8 x^{3} + x^{2} + 8 x

f (x) = \frac{5}{( x - 3 ) ^{2}}

f (x) = \frac{1}{2} x + 1

What is the inflection x^4-2x^2+3 ?
The inflection x^4-2x^2+3 is (-1/(sqrt(3)), 22/9),(1/(sqrt(3)), 22/9)