What is the critical f(x)=sqrt(8-x^3) ?

The critical f(x)=sqrt(8-x^3) is x=0,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=sqrt(8-x^3)

critical points

f (x) = 8 - x^{3}

x = 0, x = 2

Solution steps

8 - x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

8 - x^{3} : x \leq 2

All critical points are in domain

x = 0, x = 2

f (x) = x + 4

f (x) = 5 sec (x) - 4 x

f (x) = - x^{3} - 6 x^{2} + 3

f (x) = \frac{5 x ^{2} - 3}{x + 2}

x + 15

What is the critical f(x)=sqrt(8-x^3) ?
The critical f(x)=sqrt(8-x^3) is x=0,x=2