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Popular >

extreme y=x^2+4x+7

Solution

extreme points

y = x^{2} + 4 x + 7

Solution

Minimum (- 2, 3)

Solution steps

f^{'} (x) = 2 x + 4

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{2} + 4 x + 7 : 3

Minimum (- 2, 3)

Popular Examples

critical f(x)=x^2+x-2 critical points

f (x) = x^{2} + x - 2

midpoint (1/2 , 1/3),(3/2 ,(-5)/3)midpoint

(\frac{1}{2}, \frac{1}{3}), (\frac{3}{2}, \frac{- 5}{3})

extreme f(x)=2.2+2.2x-0.6x^2 extreme points

f (x) = 2.2 + 2.2 x - 0.6 x^{2}

critical x^3-9x^2+15x-8 critical points

x^{3} - 9 x^{2} + 15 x - 8

domain of f(x)=sqrt(3x-12)domain

f (x) = 3 x - 12

Frequently Asked Questions (FAQ)

What is the extreme y=x^2+4x+7 ?
The extreme y=x^2+4x+7 is Minimum(-2,3)