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Popular >

y=x^2+4x+3

Solution

y = x^{2} + 4 x + 3

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - 1

X Intercepts : (- 1, 0), (- 3, 0), Y Intercepts : (0, 3)

Vertex : Minimum (- 2, - 1)

Inverse : - 2 + x + 1, - x + 1 - 2

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 1, \infty)

Solution steps

Domain of

x^{2} + 4 x + 3 : - \infty < x < \infty

Range of

x^{2} + 4 x + 3 : f (x) \geq - 1

Axis interception points of

x^{2} + 4 x + 3 :

X Intercepts

: (- 1, 0), (- 3, 0),

Y Intercepts

: (0, 3)

Vertex of

x^{2} + 4 x + 3 :

Minimum

(- 2, - 1)

Inverse of

x^{2} + 4 x + 3 : - 2 + x + 1, - x + 1 - 2

Popular Examples

critical f(x)= x/(x^2+1)critical points

f (x) = \frac{x}{x ^{2} + 1}

domain of f(x)=(sqrt(5+x))/(2-x)domain

f (x) = \frac{5 + x}{2 - x}

perpendicular 3/2 x+2y= 15/2 ,(-4,4)perpendicular

\frac{3}{2} x + 2 y = \frac{15}{2}, (- 4, 4)

parallel 7x+5y=-40 parallel

7 x + 5 y = - 40

midpoint (11.2,-2.2),(5.2,-10.2)midpoint

(11.2, - 2.2), (5.2, - 10.2)

Frequently Asked Questions (FAQ)

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