What is the domain of f(10)= 1/(sqrt(x-1)) ?

The domain of f(10)= 1/(sqrt(x-1)) is x>1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(10)= 1/(sqrt(x-1))

domain

f (10) = \frac{1}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

f (x) = 5 x + 15

f (x) = t - 16

5 x^{2} - 4 y^{2} = 2

(- 3, - 4), (- 5, - 3)

f (x) = - x^{2} + 4 x - 4

What is the domain of f(10)= 1/(sqrt(x-1)) ?
The domain of f(10)= 1/(sqrt(x-1)) is x>1